(3x+5)(2x-8)=6x^2-24x

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Solution for (3x+5)(2x-8)=6x^2-24x equation: 



(3x+5)(2x-8)=6x^2-24x

We move all terms to the left:

(3x+5)(2x-8)-(6x^2-24x)=0

We get rid of parentheses

-6x^2+(3x+5)(2x-8)+24x=0

We multiply parentheses ..

-6x^2+(+6x^2-24x+10x-40)+24x=0

We get rid of parentheses

-6x^2+6x^2-24x+10x+24x-40=0

We add all the numbers together, and all the variables

10x-40=0

We move all terms containing x to the left, all other terms to the right

10x=40

x=40/10

x=4

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